CVE-2022-48660
Description
From CVE.org
In the Linux kernel, the following vulnerability has been resolved: gpiolib: cdev: Set lineevent_state::irq after IRQ register successfully When running gpio test on nxp-ls1028 platform with below command gpiomon --num-events=3 --rising-edge gpiochip1 25 There will be a warning trace as below: Call trace: free_irq+0x204/0x360 lineevent_free+0x64/0x70 gpio_ioctl+0x598/0x6a0 __arm64_sys_ioctl+0xb4/0x100 invoke_syscall+0x5c/0x130 ...... el0t_64_sync+0x1a0/0x1a4 The reason of this issue is that calling request_threaded_irq() function failed, and then lineevent_free() is invoked to release the resource. Since the lineevent_state::irq was already set, so the subsequent invocation of free_irq() would trigger the above warning call trace. To fix this issue, set the lineevent_state::irq after the IRQ register successfully.
Common Vulnerability Scoring System (CVSS) Score Details
Info alert:Important note
CVSS scores for open source components depend on vendor-specific factors (e.g. version or build chain). Therefore, Red Hat's score and impact rating can be different from NVD and other vendors. Red Hat remains the authoritative CVE Naming Authority (CNA) source for its products and services (see Red Hat classifications).
The following CVSS metrics and score provided are preliminary and subject to review.
CVSS v3 Score Breakdown
| Red Hat | NVD | cve.org | |
|---|---|---|---|
| Base Score | 5.5 | 5.5 | N/A |
| Attack Vector | Local | Local | N/A |
| Attack Complexity | Low | Low | N/A |
| Privileges Required | Low | Low | N/A |
| User Interaction | None | None | N/A |
| Scope | Unchanged | Unchanged | N/A |
| Confidentiality | None | None | N/A |
| Integrity Impact | None | None | N/A |
| Availability Impact | High | High | N/A |
Vector
Red Hat: CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:N/I:N/A:H
NVD: CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:N/I:N/A:H
Understanding the Weakness (CWE)
Integrity,Confidentiality,Availability
Technical Impact: Modify Memory; Execute Unauthorized Code or Commands
When a program calls free() twice with the same argument, the program's memory management data structures may become corrupted, potentially leading to the reading or modification of unexpected memory addresses. This corruption can cause the program to crash or, in some circumstances, cause two later calls to malloc() to return the same pointer. If malloc() returns the same value twice and the program later gives the attacker control over the data that is written into this doubly-allocated memory, the program becomes vulnerable to a buffer overflow attack. Doubly freeing memory may result in a write-what-where condition, allowing an attacker to execute arbitrary code.
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