CVE-2015-3331

Description

A buffer overflow flaw was found in the way the Linux kernel's Intel AES-NI instructions optimized version of the RFC4106 GCM mode decryption functionality handled fragmented packets. A remote attacker could use this flaw to crash, or potentially escalate their privileges on, a system over a connection with an active AES-GCM mode IPSec security association.

Statement

This issue does not affect the version of the kernel package as shipped with Red Hat Enterprise Linux 5.

This issue affects the versions of Linux kernel as shipped with Red Hat Enterprise Linux 6, 7 and Red Hat Enterprise MRG 2. Future kernel updates for Red Hat Enterprise Linux 6 may address this issue.

Common Vulnerability Scoring System (CVSS) Score Details

Info alert:Important note

CVSS scores for open source components depend on vendor-specific factors (e.g. version or build chain). Therefore, Red Hat's score and impact rating can be different from NVD and other vendors. Red Hat remains the authoritative CVE Naming Authority (CNA) source for its products and services (see Red Hat classifications).

CVSS v2 Score Breakdown

Red HatNVDcve.org
Base Score7.19.3N/A
Attack VectorNetworkNetworkN/A
Access ComplexityHighMediumN/A
AuthenticationSingleNoneN/A
Confidentiality ImpactCompleteCompleteN/A
Integrity ImpactCompleteCompleteN/A
Availability ImpactCompleteCompleteN/A

Vector

Red Hat: AV:N/AC:H/Au:S/C:C/I:C/A:C

NVD: AV:N/AC:M/Au:N/C:C/I:C/A:C

Understanding the Weakness (CWE)

Integrity,Confidentiality,Availability

Technical Impact: Modify Memory; Execute Unauthorized Code or Commands

Buffer overflows often can be used to execute arbitrary code, which is usually outside the scope of the product's implicit security policy. This can often be used to subvert any other security service.

Availability

Technical Impact: Modify Memory; DoS: Crash, Exit, or Restart; DoS: Resource Consumption (CPU)

Buffer overflows generally lead to crashes. Other attacks leading to lack of availability are possible, including putting the product into an infinite loop.

Frequently Asked Questions

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