Issue

• Using search predicates to the underlying JPA implementation (Hibernate 4.2.7SP1)

• If I create a LIKE predicate with an escape character, I get multiple NullPointerException occurrences when trying to process the resulting SQL prepared statement.

• This appears to be because the escape character is added as an additional parameter in the prepared statement and no type information is provided.

• That seems at odds with the code in the registerParameters() implementation, but I get no stack trace for any of the exceptions.

• Following is an example of generated SQL:

select count(user0_.id) as col_0_0_ from organization_user user0_ where user0_.organization_name like ? escape '\' and (lower(user0_.username) like ? escape ? or lower(user0_.given_name) like ? escape ?)

• The expectation is that, the escape character would have been treated as a literal and added to the text. Instead, the code in org.hibernate.ejb.criteria.predicate.LikePredicate renders the escape as an additional parameter.